Resolver ((5+36+36+38+4+45)*3+45-36+36+19*135)div(22+135=

$$((5+36+36+38+4+45) \times 3+45-36+36+19 \times 135) \div (22+135=$$

Calcular

$$\frac{3102}{157}\approx 19.757961783$$

Pasos da solución

Suma 5 e 36 para obter 41.

$$\frac{\left(41+36+38+4+45\right)\times 3+45-36+36+19\times 135}{22+135}$$

Suma 41 e 36 para obter 77.

$$\frac{\left(77+38+4+45\right)\times 3+45-36+36+19\times 135}{22+135}$$

Suma 77 e 38 para obter 115.

$$\frac{\left(115+4+45\right)\times 3+45-36+36+19\times 135}{22+135}$$

Suma 115 e 4 para obter 119.

$$\frac{\left(119+45\right)\times 3+45-36+36+19\times 135}{22+135}$$

Suma 119 e 45 para obter 164.

$$\frac{164\times 3+45-36+36+19\times 135}{22+135}$$

Multiplica 164 e 3 para obter 492.

$$\frac{492+45-36+36+19\times 135}{22+135}$$

Suma 492 e 45 para obter 537.

$$\frac{537-36+36+19\times 135}{22+135}$$

Resta 36 de 537 para obter 501.

$$\frac{501+36+19\times 135}{22+135}$$

Suma 501 e 36 para obter 537.

$$\frac{537+19\times 135}{22+135}$$

Multiplica 19 e 135 para obter 2565.

$$\frac{537+2565}{22+135}$$

Suma 537 e 2565 para obter 3102.

$$\frac{3102}{22+135}$$

Suma 22 e 135 para obter 157.

$$\frac{3102}{157}$$

Factorizar

$$\frac{2 \cdot 3 \cdot 11 \cdot 47}{157} = 19\frac{119}{157} = 19.75796178343949$$