Resolver (675+(-45)*12/8)*(-11/8)^3

$$( 675 + ( - 45 ) \cdot 1 \frac { 2 } { 8 } ) \cdot ( - 1 \frac { 1 } { 8 } ) ^ { 3 }$$

Calcular

$$-\frac{1804275}{2048}=-880.993652344$$

Pasos da solución

Multiplica 1 e 8 para obter 8.

$$\left(675-45\times \frac{8+2}{8}\right)\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Suma 8 e 2 para obter 10.

$$\left(675-45\times \frac{10}{8}\right)\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Reduce a fracción \frac{10}{8} a termos máis baixos extraendo e cancelando 2.

$$\left(675-45\times \frac{5}{4}\right)\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Multiplica -45 e \frac{5}{4} para obter -\frac{225}{4}.

$$\left(675-\frac{225}{4}\right)\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Resta \frac{225}{4} de 675 para obter \frac{2475}{4}.

$$\frac{2475}{4}\left(-\frac{1\times 8+1}{8}\right)^{3}$$

Multiplica 1 e 8 para obter 8.

$$\frac{2475}{4}\left(-\frac{8+1}{8}\right)^{3}$$

Suma 8 e 1 para obter 9.

$$\frac{2475}{4}\left(-\frac{9}{8}\right)^{3}$$

Calcula -\frac{9}{8} á potencia de 3 e obtén -\frac{729}{512}.

$$\frac{2475}{4}\left(-\frac{729}{512}\right)$$

Multiplica \frac{2475}{4} e -\frac{729}{512} para obter -\frac{1804275}{2048}.

$$-\frac{1804275}{2048}$$

Factorizar

$$-\frac{1804275}{2048} = -880\frac{2035}{2048} = -880.99365234375$$