Resolver (5t_{6}+3+a+b-a)+20=3.05

$$( 5 t _ { 6 } + 3 + a + b - a ) + 20 = 3.05$$

Resolver b

$$b=-5t_{6}-19.95$$

Pasos da solución

Combina a e -a para obter 0.

$$5t_{6}+3+b+20=3.05$$

Suma 3 e 20 para obter 23.

$$5t_{6}+23+b=3.05$$

Resta 5t_{6} en ambos lados.

$$23+b=3.05-5t_{6}$$

Resta 23 en ambos lados.

$$b=3.05-5t_{6}-23$$

Resta 23 de 3.05 para obter -19.95.

$$b=-19.95-5t_{6}$$

Resolver a (complex solution)

$$a\in \mathrm{C}$$

$$t_{6}=-\frac{b}{5}-\frac{399}{100}$$

Resolver a

$$a\in \mathrm{R}$$

$$t_{6}=-\frac{b}{5}-\frac{399}{100}$$