Resolver (4*10^3)^3*(-0125*10^2)^2=

$$( 4 \times 10 ^ { 3 } ) ^ { 3 } \cdot ( - 0125 \times 10 ^ { 2 } ) ^ { 2 } =$$

Calcular

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Pasos da solución

Calcula 10 á potencia de 3 e obtén 1000.

$$\left(4\times 1000\right)^{3}\times \left(0\times 125\times 10^{2}\right)^{2}$$

Multiplica 4 e 1000 para obter 4000.

$$4000^{3}\times \left(0\times 125\times 10^{2}\right)^{2}$$

Calcula 4000 á potencia de 3 e obtén 64000000000.

$$64000000000\times \left(0\times 125\times 10^{2}\right)^{2}$$

Multiplica 0 e 125 para obter 0.

$$64000000000\times \left(0\times 10^{2}\right)^{2}$$

Calcula 10 á potencia de 2 e obtén 100.

$$64000000000\times \left(0\times 100\right)^{2}$$

Multiplica 0 e 100 para obter 0.

$$64000000000\times 0^{2}$$

Calcula 0 á potencia de 2 e obtén 0.

$$64000000000\times 0$$

Multiplica 64000000000 e 0 para obter 0.

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Factorizar

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