Resolver (1-sqrt[3]{-8})-(10^-4+1/10)

$$( 1 - \sqrt[ 3 ] { - 8 } ) - ( 10 ^ { - 4 } + \frac { 1 } { 10 } )$$

Calcular

$$\frac{28999}{10000}=2.8999$$

Pasos da solución

Calcular \sqrt[3]{-8} e obter -2.

$$1-\left(-2\right)-\left(10^{-4}+\frac{1}{10}\right)$$

O contrario de -2 é 2.

$$1+2-\left(10^{-4}+\frac{1}{10}\right)$$

Suma 1 e 2 para obter 3.

$$3-\left(10^{-4}+\frac{1}{10}\right)$$

Calcula 10 á potencia de -4 e obtén \frac{1}{10000}.

$$3-\left(\frac{1}{10000}+\frac{1}{10}\right)$$

Suma \frac{1}{10000} e \frac{1}{10} para obter \frac{1001}{10000}.

$$3-\frac{1001}{10000}$$

Resta \frac{1001}{10000} de 3 para obter \frac{28999}{10000}.

$$\frac{28999}{10000}$$

Factorizar

$$\frac{47 \cdot 617}{2 ^ {4} \cdot 5 ^ {4}} = 2\frac{8999}{10000} = 2.8999$$