Resolver ((2-1/4)*(3-1/2))^2-sqrt{9}

$$( ( 2 - \frac { 1 } { 4 } ) \cdot ( 3 - \frac { 1 } { 2 } ) ) ^ { 2 } - \sqrt { 9 }$$

Calcular

$$\frac{1033}{64}=16.140625$$

Pasos da solución

Resta \frac{1}{4} de 2 para obter \frac{7}{4}.

$$\left(\frac{7}{4}\left(3-\frac{1}{2}\right)\right)^{2}-\sqrt{9}$$

Resta \frac{1}{2} de 3 para obter \frac{5}{2}.

$$\left(\frac{7}{4}\times \frac{5}{2}\right)^{2}-\sqrt{9}$$

Multiplica \frac{7}{4} e \frac{5}{2} para obter \frac{35}{8}.

$$\left(\frac{35}{8}\right)^{2}-\sqrt{9}$$

Calcula \frac{35}{8} á potencia de 2 e obtén \frac{1225}{64}.

$$\frac{1225}{64}-\sqrt{9}$$

Calcular a raíz cadrada de 9 e obter 3.

$$\frac{1225}{64}-3$$

Resta 3 de \frac{1225}{64} para obter \frac{1033}{64}.

$$\frac{1033}{64}$$

Factorizar

$$\frac{1033}{2 ^ {6}} = 16\frac{9}{64} = 16.140625$$