Resolver (4/9)^2/2+sqrt[3]{-27}+(1/5)^2+sqrt[3]{-8/27}+(3/5)^0

$$( \frac { 4 } { 9 } ) ^ { 2 / 2 } + \sqrt[ 3 ] { - 27 } + ( \frac { 1 } { 5 } ) ^ { 2 } + \sqrt[ 3 ] { - \frac { 8 } { 27 } } + ( \frac { 3 } { 5 } ) ^ { 0 }$$

Calcular

$$-\frac{491}{225}\approx -2.182222222$$

Pasos da solución

Divide 2 entre 2 para obter 1.

$$\left(\frac{4}{9}\right)^{1}+\sqrt[3]{-27}+\left(\frac{1}{5}\right)^{2}+\sqrt[3]{-\frac{8}{27}}+\left(\frac{3}{5}\right)^{0}$$

Calcula \frac{4}{9} á potencia de 1 e obtén \frac{4}{9}.

$$\frac{4}{9}+\sqrt[3]{-27}+\left(\frac{1}{5}\right)^{2}+\sqrt[3]{-\frac{8}{27}}+\left(\frac{3}{5}\right)^{0}$$

Calcular \sqrt[3]{-27} e obter -3.

$$\frac{4}{9}-3+\left(\frac{1}{5}\right)^{2}+\sqrt[3]{-\frac{8}{27}}+\left(\frac{3}{5}\right)^{0}$$

Resta 3 de \frac{4}{9} para obter -\frac{23}{9}.

$$-\frac{23}{9}+\left(\frac{1}{5}\right)^{2}+\sqrt[3]{-\frac{8}{27}}+\left(\frac{3}{5}\right)^{0}$$

Calcula \frac{1}{5} á potencia de 2 e obtén \frac{1}{25}.

$$-\frac{23}{9}+\frac{1}{25}+\sqrt[3]{-\frac{8}{27}}+\left(\frac{3}{5}\right)^{0}$$

Suma -\frac{23}{9} e \frac{1}{25} para obter -\frac{566}{225}.

$$-\frac{566}{225}+\sqrt[3]{-\frac{8}{27}}+\left(\frac{3}{5}\right)^{0}$$

Calcular \sqrt[3]{-\frac{8}{27}} e obter -\frac{2}{3}.

$$-\frac{566}{225}-\frac{2}{3}+\left(\frac{3}{5}\right)^{0}$$

Resta \frac{2}{3} de -\frac{566}{225} para obter -\frac{716}{225}.

$$-\frac{716}{225}+\left(\frac{3}{5}\right)^{0}$$

Calcula \frac{3}{5} á potencia de 0 e obtén 1.

$$-\frac{716}{225}+1$$

Suma -\frac{716}{225} e 1 para obter -\frac{491}{225}.

$$-\frac{491}{225}$$

Factorizar

$$-\frac{491}{225} = -2\frac{41}{225} = -2.1822222222222223$$