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\frac{1}{9}+\left(\frac{2}{5}\right)^{-1}
Calcula \frac{1}{3} á potencia de 2 e obtén \frac{1}{9}.
\frac{1}{9}+\frac{5}{2}
Calcula \frac{2}{5} á potencia de -1 e obtén \frac{5}{2}.
\frac{47}{18}
Suma \frac{1}{9} e \frac{5}{2} para obter \frac{47}{18}.