Resolver {left(61/2right)}^3-21^2/4-1

$${ \left(6 \frac{ 1 }{ 2 } \right) }^{ 3 } -2 \frac{ { 1 }^{ 2 } }{ 4 } -1$$

Calcular

$$\frac{2185}{8}=273.125$$

Pasos da solución

Multiplica 6 e 2 para obter 12.

$$\left(\frac{12+1}{2}\right)^{3}-2\times \frac{1^{2}}{4}-1$$

Suma 12 e 1 para obter 13.

$$\left(\frac{13}{2}\right)^{3}-2\times \frac{1^{2}}{4}-1$$

Calcula \frac{13}{2} á potencia de 3 e obtén \frac{2197}{8}.

$$\frac{2197}{8}-2\times \frac{1^{2}}{4}-1$$

Calcula 1 á potencia de 2 e obtén 1.

$$\frac{2197}{8}-2\times \frac{1}{4}-1$$

Multiplica 2 e \frac{1}{4} para obter \frac{1}{2}.

$$\frac{2197}{8}-\frac{1}{2}-1$$

Resta \frac{1}{2} de \frac{2197}{8} para obter \frac{2193}{8}.

$$\frac{2193}{8}-1$$

Resta 1 de \frac{2193}{8} para obter \frac{2185}{8}.

$$\frac{2185}{8}$$

Factorizar

$$\frac{5 \cdot 19 \cdot 23}{2 ^ {3}} = 273\frac{1}{8} = 273.125$$