Resolver sqrt[4]{1/81}+(2/3)^-1-0002*10^3

$$\sqrt[ 4 ] { \frac { 1 } { 81 } } + ( \frac { 2 } { 3 } ) ^ { - 1 } - 0002 \times 10 ^ { 3 }$$

Calcular

$$\frac{11}{6}\approx 1.833333333$$

Pasos da solución

Calcular \sqrt[4]{\frac{1}{81}} e obter \frac{1}{3}.

$$\frac{1}{3}+\left(\frac{2}{3}\right)^{-1}-0\times 0\times 0\times 2\times 10^{3}$$

Calcula \frac{2}{3} á potencia de -1 e obtén \frac{3}{2}.

$$\frac{1}{3}+\frac{3}{2}-0\times 0\times 0\times 2\times 10^{3}$$

Suma \frac{1}{3} e \frac{3}{2} para obter \frac{11}{6}.

$$\frac{11}{6}-0\times 0\times 0\times 2\times 10^{3}$$

Multiplica 0 e 0 para obter 0.

$$\frac{11}{6}-0\times 0\times 2\times 10^{3}$$

Multiplica 0 e 0 para obter 0.

$$\frac{11}{6}-0\times 2\times 10^{3}$$

Multiplica 0 e 2 para obter 0.

$$\frac{11}{6}-0\times 10^{3}$$

Calcula 10 á potencia de 3 e obtén 1000.

$$\frac{11}{6}-0\times 1000$$

Multiplica 0 e 1000 para obter 0.

$$\frac{11}{6}-0$$

Resta 0 de \frac{11}{6} para obter \frac{11}{6}.

$$\frac{11}{6}$$

Factorizar

$$\frac{11}{2 \cdot 3} = 1\frac{5}{6} = 1.8333333333333333$$