Resolver sqrt[4]{1/81}+(2/3)^-1-0.002*10^3

$$\sqrt[ 4 ] { \frac { 1 } { 81 } } + ( \frac { 2 } { 3 } ) ^ { - 1 } - 0.002 \times 10 ^ { 3 }$$

Calcular

$$-\frac{1}{6}\approx -0.166666667$$

Pasos da solución

Calcular \sqrt[4]{\frac{1}{81}} e obter \frac{1}{3}.

$$\frac{1}{3}+\left(\frac{2}{3}\right)^{-1}-0.002\times 10^{3}$$

Calcula \frac{2}{3} á potencia de -1 e obtén \frac{3}{2}.

$$\frac{1}{3}+\frac{3}{2}-0.002\times 10^{3}$$

Suma \frac{1}{3} e \frac{3}{2} para obter \frac{11}{6}.

$$\frac{11}{6}-0.002\times 10^{3}$$

Calcula 10 á potencia de 3 e obtén 1000.

$$\frac{11}{6}-0.002\times 1000$$

Multiplica 0.002 e 1000 para obter 2.

$$\frac{11}{6}-2$$

Resta 2 de \frac{11}{6} para obter -\frac{1}{6}.

$$-\frac{1}{6}$$

Factorizar

$$-\frac{1}{6} = -0.16666666666666666$$