Resolver sqrt[3]{27}-4sqrt{64}+3sqrt[4]{625}+5sqrt{25}-9sqrt{273}

$$\sqrt[ 3 ] { 27 } - 4 \sqrt { 64 } + 3 \sqrt[ 4 ] { 625 } + 5 \sqrt { 25 } - 9 \sqrt { 273 }$$

Calcular

$$11-9\sqrt{273}\approx -137.704404777$$

Pasos da solución

Calcular \sqrt[3]{27} e obter 3.

$$3-4\sqrt{64}+3\sqrt[4]{625}+5\sqrt{25}-9\sqrt{273}$$

Calcular a raíz cadrada de 64 e obter 8.

$$3-4\times 8+3\sqrt[4]{625}+5\sqrt{25}-9\sqrt{273}$$

Multiplica -4 e 8 para obter -32.

$$3-32+3\sqrt[4]{625}+5\sqrt{25}-9\sqrt{273}$$

Resta 32 de 3 para obter -29.

$$-29+3\sqrt[4]{625}+5\sqrt{25}-9\sqrt{273}$$

Calcular \sqrt[4]{625} e obter 5.

$$-29+3\times 5+5\sqrt{25}-9\sqrt{273}$$

Multiplica 3 e 5 para obter 15.

$$-29+15+5\sqrt{25}-9\sqrt{273}$$

Suma -29 e 15 para obter -14.

$$-14+5\sqrt{25}-9\sqrt{273}$$

Calcular a raíz cadrada de 25 e obter 5.

$$-14+5\times 5-9\sqrt{273}$$

Multiplica 5 e 5 para obter 25.

$$-14+25-9\sqrt{273}$$

Suma -14 e 25 para obter 11.

$$11-9\sqrt{273}$$