Resolver sqrt[3]{646/125-11}-sqrt{01^-2}+sqrt[3]{8^2}

$$\sqrt[ 3 ] { \frac { 646 } { 125 } - 11 } - \sqrt { 01 ^ { - 2 } } + \sqrt[ 3 ] { 8 ^ { 2 } }$$

Calcular

$$\frac{11}{5}=2.2$$

Pasos da solución

Resta 11 de \frac{646}{125} para obter -\frac{729}{125}.

$$\sqrt[3]{-\frac{729}{125}}-\sqrt{0\times 1^{-2}}+\sqrt[3]{8^{2}}$$

Calcular \sqrt[3]{-\frac{729}{125}} e obter -\frac{9}{5}.

$$-\frac{9}{5}-\sqrt{0\times 1^{-2}}+\sqrt[3]{8^{2}}$$

Calcula 1 á potencia de -2 e obtén 1.

$$-\frac{9}{5}-\sqrt{0\times 1}+\sqrt[3]{8^{2}}$$

Multiplica 0 e 1 para obter 0.

$$-\frac{9}{5}-\sqrt{0}+\sqrt[3]{8^{2}}$$

Calcular a raíz cadrada de 0 e obter 0.

$$-\frac{9}{5}-0+\sqrt[3]{8^{2}}$$

Multiplica -1 e 0 para obter 0.

$$-\frac{9}{5}+0+\sqrt[3]{8^{2}}$$

Suma -\frac{9}{5} e 0 para obter -\frac{9}{5}.

$$-\frac{9}{5}+\sqrt[3]{8^{2}}$$

Calcula 8 á potencia de 2 e obtén 64.

$$-\frac{9}{5}+\sqrt[3]{64}$$

Calcular \sqrt[3]{64} e obter 4.

$$-\frac{9}{5}+4$$

Suma -\frac{9}{5} e 4 para obter \frac{11}{5}.

$$\frac{11}{5}$$

Factorizar

$$\frac{11}{5} = 2\frac{1}{5} = 2.2$$