Resolver sqrt[3]{646/125-11}-sqrt{0.1^-2}+sqrt[3]{8^2}

$$\sqrt[ 3 ] { \frac { 646 } { 125 } - 11 } - \sqrt { 0.1 ^ { - 2 } } + \sqrt[ 3 ] { 8 ^ { 2 } }$$

Calcular

$$-7.8$$

Pasos da solución

Resta 11 de \frac{646}{125} para obter -\frac{729}{125}.

$$\sqrt[3]{-\frac{729}{125}}-\sqrt{0.1^{-2}}+\sqrt[3]{8^{2}}$$

Calcular \sqrt[3]{-\frac{729}{125}} e obter -\frac{9}{5}.

$$-\frac{9}{5}-\sqrt{0.1^{-2}}+\sqrt[3]{8^{2}}$$

Calcula 0.1 á potencia de -2 e obtén 100.

$$-\frac{9}{5}-\sqrt{100}+\sqrt[3]{8^{2}}$$

Calcular a raíz cadrada de 100 e obter 10.

$$-\frac{9}{5}-10+\sqrt[3]{8^{2}}$$

Resta 10 de -\frac{9}{5} para obter -\frac{59}{5}.

$$-\frac{59}{5}+\sqrt[3]{8^{2}}$$

Calcula 8 á potencia de 2 e obtén 64.

$$-\frac{59}{5}+\sqrt[3]{64}$$

Calcular \sqrt[3]{64} e obter 4.

$$-\frac{59}{5}+4$$

Suma -\frac{59}{5} e 4 para obter -\frac{39}{5}.

$$-\frac{39}{5}$$

Factorizar

$$-7.8$$