Resolver sqrt[3]{9{left(1-frac{1/3right)}^2-3/2}{2+1/2}}

$$\sqrt[ 3 ]{ \frac{ 9 { \left(1- \frac{ 1 }{ 3 } \right) }^{ 2 } - \frac{ 3 }{ 2 } }{ 2+ \frac{ 1 }{ 2 } } }$$

Calcular

$$1$$

Pasos da solución

Resta \frac{1}{3} de 1 para obter \frac{2}{3}.

$$\sqrt[3]{\frac{9\times \left(\frac{2}{3}\right)^{2}-\frac{3}{2}}{2+\frac{1}{2}}}$$

Calcula \frac{2}{3} á potencia de 2 e obtén \frac{4}{9}.

$$\sqrt[3]{\frac{9\times \frac{4}{9}-\frac{3}{2}}{2+\frac{1}{2}}}$$

Multiplica 9 e \frac{4}{9} para obter 4.

$$\sqrt[3]{\frac{4-\frac{3}{2}}{2+\frac{1}{2}}}$$

Resta \frac{3}{2} de 4 para obter \frac{5}{2}.

$$\sqrt[3]{\frac{\frac{5}{2}}{2+\frac{1}{2}}}$$

Suma 2 e \frac{1}{2} para obter \frac{5}{2}.

$$\sqrt[3]{\frac{\frac{5}{2}}{\frac{5}{2}}}$$

Divide \frac{5}{2} entre \frac{5}{2} para obter 1.

$$\sqrt[3]{1}$$

Calcular \sqrt[3]{1} e obter 1.

$$1$$

Factorizar

$$1$$