Resolver {l}{-15+10+7-8=-6quad-33}{42+(-5)-(-39)+4=(42+-5)(39+4)}

$$\left. \begin{array} { l } { - 15 + 10 + 7 - 8 = - 6 \quad - 33 } \\ { 42 + ( - 5 ) - ( - 39 ) + 4 = ( 42 + - 5 ) ( 39 + 4 ) } \end{array} \right.$$

Verificar

Pasos da solución

Suma -15 e 10 para obter -5.

$$-5+7-8=-6-33\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Suma -5 e 7 para obter 2.

$$2-8=-6-33\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Resta 8 de 2 para obter -6.

$$-6=-6-33\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Resta 33 de -6 para obter -39.

$$-6=-39\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Comparar -6 e -39.

$$\text{false}\text{ and }42-5-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

Resta 5 de 42 para obter 37.

$$\text{false}\text{ and }37-\left(-39\right)+4=\left(42-5\right)\left(39+4\right)$$

O contrario de -39 é 39.

$$\text{false}\text{ and }37+39+4=\left(42-5\right)\left(39+4\right)$$

Suma 37 e 39 para obter 76.

$$\text{false}\text{ and }76+4=\left(42-5\right)\left(39+4\right)$$

Suma 76 e 4 para obter 80.

$$\text{false}\text{ and }80=\left(42-5\right)\left(39+4\right)$$

Resta 5 de 42 para obter 37.

$$\text{false}\text{ and }80=37\left(39+4\right)$$

Suma 39 e 4 para obter 43.

$$\text{false}\text{ and }80=37\times 43$$

Multiplica 37 e 43 para obter 1591.

$$\text{false}\text{ and }80=1591$$

Comparar 80 e 1591.

$$\text{false}\text{ and }\text{false}$$

A conxunción de \text{false} e \text{false} é \text{false}.

$$\text{false}$$