Resolver {l}{(3^2+45^1+4+16)(5+10)=0}{5^3+149^2+605+200=0}

$$\left. \begin{array} { l } { ( 3 ^ { 2 } + 45 ^ { 1 } + 4 + 16 ) ( 5 + 10 ) = 0 } \\ { 5 ^ { 3 } + 149 ^ { 2 } + 605 + 200 = 0 } \end{array} \right.$$

Verificar

Pasos da solución

Calcula 3 á potencia de 2 e obtén 9.

$$\left(9+45^{1}+4+16\right)\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Calcula 45 á potencia de 1 e obtén 45.

$$\left(9+45+4+16\right)\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Suma 9 e 45 para obter 54.

$$\left(54+4+16\right)\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Suma 54 e 4 para obter 58.

$$\left(58+16\right)\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Suma 58 e 16 para obter 74.

$$74\left(5+10\right)=0\text{ and }5^{3}+149^{2}+605+200=0$$

Suma 5 e 10 para obter 15.

$$74\times 15=0\text{ and }5^{3}+149^{2}+605+200=0$$

Multiplica 74 e 15 para obter 1110.

$$1110=0\text{ and }5^{3}+149^{2}+605+200=0$$

Comparar 1110 e 0.

$$\text{false}\text{ and }5^{3}+149^{2}+605+200=0$$

Calcula 5 á potencia de 3 e obtén 125.

$$\text{false}\text{ and }125+149^{2}+605+200=0$$

Calcula 149 á potencia de 2 e obtén 22201.

$$\text{false}\text{ and }125+22201+605+200=0$$

Suma 125 e 22201 para obter 22326.

$$\text{false}\text{ and }22326+605+200=0$$

Suma 22326 e 605 para obter 22931.

$$\text{false}\text{ and }22931+200=0$$

Suma 22931 e 200 para obter 23131.

$$\text{false}\text{ and }23131=0$$

Comparar 23131 e 0.

$$\text{false}\text{ and }\text{false}$$

A conxunción de \text{false} e \text{false} é \text{false}.

$$\text{false}$$