Resolver {l}{(1+4+3)-(8+2)+(11+6):17=151}{18*6:27-[26-(81:9*2:3+3*6)]=[2]}

$$\left. \begin{array} { l } { ( 1 + 4 + 3 ) - ( 8 + 2 ) + ( 11 + 6 ) : 17 = 151 } \\ { 18 \cdot 6 : 27 - [ 26 - ( 81 : 9 \cdot 2 : 3 + 3 \cdot 6 ) ] = [ 2 ] } \end{array} \right.$$

Verificar

Pasos da solución

Suma 1 e 4 para obter 5.

$$5+3-\left(8+2\right)+\frac{11+6}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Suma 5 e 3 para obter 8.

$$8-\left(8+2\right)+\frac{11+6}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Suma 8 e 2 para obter 10.

$$8-10+\frac{11+6}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Resta 10 de 8 para obter -2.

$$-2+\frac{11+6}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Suma 11 e 6 para obter 17.

$$-2+\frac{17}{17}=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Divide 17 entre 17 para obter 1.

$$-2+1=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Suma -2 e 1 para obter -1.

$$-1=151\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Comparar -1 e 151.

$$\text{false}\text{ and }\frac{18\times 6}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Multiplica 18 e 6 para obter 108.

$$\text{false}\text{ and }\frac{108}{27}-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Divide 108 entre 27 para obter 4.

$$\text{false}\text{ and }4-\left(26-\left(\frac{\frac{81}{9}\times 2}{3}+3\times 6\right)\right)=2$$

Divide 81 entre 9 para obter 9.

$$\text{false}\text{ and }4-\left(26-\left(\frac{9\times 2}{3}+3\times 6\right)\right)=2$$

Multiplica 9 e 2 para obter 18.

$$\text{false}\text{ and }4-\left(26-\left(\frac{18}{3}+3\times 6\right)\right)=2$$

Divide 18 entre 3 para obter 6.

$$\text{false}\text{ and }4-\left(26-\left(6+3\times 6\right)\right)=2$$

Multiplica 3 e 6 para obter 18.

$$\text{false}\text{ and }4-\left(26-\left(6+18\right)\right)=2$$

Suma 6 e 18 para obter 24.

$$\text{false}\text{ and }4-\left(26-24\right)=2$$

Resta 24 de 26 para obter 2.

$$\text{false}\text{ and }4-2=2$$

Resta 2 de 4 para obter 2.

$$\text{false}\text{ and }2=2$$

Comparar 2 e 2.

$$\text{false}\text{ and }\text{true}$$

A conxunción de \text{false} e \text{true} é \text{false}.

$$\text{false}$$