Resolver {l}{(-3-5i)^2}{+2(-3-5i)}{+1}

$$\left. \begin{array} { l } { ( - 3 - 5 i ) ^ { 2 } } \\ { + 2 ( - 3 - 5 i ) } \\ { + 1 } \end{array} \right.$$

Calcular

$$-21+20i$$

Pasos da solución

Calcula -3-5i á potencia de 2 e obtén -16+30i.

$$-16+30i+2\left(-3-5i\right)+1$$

Fai as sumas.

$$2\left(-3-5i\right)-15+30i$$

Multiplica 2 e -3-5i para obter -6-10i.

$$-6-10i-15+30i$$

Fai as sumas.

$$-21+20i$$

Parte real

$$-21$$

Pasos da solución

Calcula -3-5i á potencia de 2 e obtén -16+30i.

$$Re(-16+30i+2\left(-3-5i\right)+1)$$

Fai as sumas en -16+30i+1.

$$Re(2\left(-3-5i\right)-15+30i)$$

Multiplica 2 e -3-5i para obter -6-10i.

$$Re(-6-10i-15+30i)$$

Fai as sumas en -6-10i-15+30i.

$$Re(-21+20i)$$

A parte real de -21+20i é -21.

$$-21$$