Resolver {l}{(sqrt{2}-1)^2+(2sqrt{2}-1)^2}{+2sqrt{2}}

$$\left. \begin{array} { l } { ( \sqrt { 2 } - 1 ) ^ { 2 } + ( 2 \sqrt { 2 } - 1 ) ^ { 2 } } \\ { + 2 \sqrt { 2 } } \end{array} \right.$$

Calcular

$$12-4\sqrt{2}\approx 6.343145751$$

Pasos da solución

Usar teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(\sqrt{2}-1\right)^{2}.

$$\left(\sqrt{2}\right)^{2}-2\sqrt{2}+1+\left(2\sqrt{2}-1\right)^{2}+2\sqrt{2}$$

O cadrado de \sqrt{2} é 2.

$$2-2\sqrt{2}+1+\left(2\sqrt{2}-1\right)^{2}+2\sqrt{2}$$

Suma 2 e 1 para obter 3.

$$3-2\sqrt{2}+\left(2\sqrt{2}-1\right)^{2}+2\sqrt{2}$$

Usar teorema binomial \left(a-b\right)^{2}=a^{2}-2ab+b^{2} para expandir \left(2\sqrt{2}-1\right)^{2}.

$$3-2\sqrt{2}+4\left(\sqrt{2}\right)^{2}-4\sqrt{2}+1+2\sqrt{2}$$

O cadrado de \sqrt{2} é 2.

$$3-2\sqrt{2}+4\times 2-4\sqrt{2}+1+2\sqrt{2}$$

Multiplica 4 e 2 para obter 8.

$$3-2\sqrt{2}+8-4\sqrt{2}+1+2\sqrt{2}$$

Suma 8 e 1 para obter 9.

$$3-2\sqrt{2}+9-4\sqrt{2}+2\sqrt{2}$$

Suma 3 e 9 para obter 12.

$$12-2\sqrt{2}-4\sqrt{2}+2\sqrt{2}$$

Combina -2\sqrt{2} e -4\sqrt{2} para obter -6\sqrt{2}.

$$12-6\sqrt{2}+2\sqrt{2}$$

Combina -6\sqrt{2} e 2\sqrt{2} para obter -4\sqrt{2}.

$$12-4\sqrt{2}$$