Resolver {l}{9^x+2=240+9^x}{y=x}{z=y}{a=z}{b=a}{c=b}{text{Solvefor}dtext{where}}{d=c}

$$\left. \begin{array} { l } { 9 ^ {x + 2} = 240 + 9 ^ {x} }\\ { y = x }\\ { z = y }\\ { a = z }\\ { b = a }\\ { c = b }\\ { \text{Solve for } d \text{ where} } \\ { d = c } \end{array} \right.$$

Resolver x, y, z, a, b, c, d (complex solution)

$$x=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$n_{1}\in \mathrm{Z}$$

$$y=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$n_{1}\in \mathrm{Z}$$

$$z\in \cup n_{1},\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$n_{1}\in \mathrm{Z}$$

$$a\in \cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$n_{1}\in \mathrm{Z}$$

$$b\in \cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$a=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{ and }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\right)$$

$$n_{1}\in \mathrm{Z}$$

$$c\in \cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$b=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{ and }a=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{ and }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}$$

$$\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\right)$$

$$\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\right)\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }a=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{, }z=\frac{1}{2}+i\ln(3)^{-1}\pi n_{1}\right)\right)\right)\right)\text{, }n_{1}\in \mathrm{Z}\text{, }d\in \cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\cup n_{1},\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{, }c=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{ and }b=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{ and }a=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{ and }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{, }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\right)\text{, }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\right)\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }a=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{, }z=\frac{1}{2}+i\ln(3)^{-1}\pi n_{1}\right)\right)\right)\right)\text{, }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }z=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\right)\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }a=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{, }z=\frac{1}{2}+i\ln(3)^{-1}\pi n_{1}\right)\right)\right)\right)\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }b=\frac{\pi n_{1}i}{\ln(3)}+\frac{1}{2}\text{, }a=\frac{1}{2}+i\ln(3)^{-1}\pi n_{1}\text{ and }z=\frac{1}{2}+i\ln(3)^{-1}\pi n_{1}\right)\right)\right)\right)\right)\text{, }\exists n_{1}\in \mathrm{Z}\text{ : }\left(\exists n_{1}\in \mathrm{Z}\text{ : }z=\frac{1}{2}+i\ln(3)^{-1}\pi n_{1}\right)\right)\right)\right)\text{, }n_{1}\in \mathrm{Z}$$

Resolver x, y, z, a, b, c, d

$$d=\frac{1}{2}=0.5$$