Resolver {l}{S=-3/2m^2+9/2m+9/2}{m=3/2}

$$\left\{ \begin{array} { l } { S = - \frac { 3 } { 2 } m ^ { 2 } + \frac { 9 } { 2 } m + \frac { 9 } { 2 } } \\ { m = \frac { 3 } { 2 } } \end{array} \right.$$

Resolver S, m

$$S = \frac{63}{8} = 7\frac{7}{8} = 7.875$$

$$m = \frac{3}{2} = 1\frac{1}{2} = 1.5$$

Pasos da solución

Ten en conta a primeira ecuación. Insire os valores coñecidos das variables na ecuación.

$$S=-\frac{3}{2}\times \left(\frac{3}{2}\right)^{2}+\frac{9}{2}\times \frac{3}{2}+\frac{9}{2}$$

Calcula \frac{3}{2} á potencia de 2 e obtén \frac{9}{4}.

$$S=-\frac{3}{2}\times \frac{9}{4}+\frac{9}{2}\times \frac{3}{2}+\frac{9}{2}$$

Multiplica -\frac{3}{2} e \frac{9}{4} para obter -\frac{27}{8}.

$$S=-\frac{27}{8}+\frac{9}{2}\times \frac{3}{2}+\frac{9}{2}$$

Multiplica \frac{9}{2} e \frac{3}{2} para obter \frac{27}{4}.

$$S=-\frac{27}{8}+\frac{27}{4}+\frac{9}{2}$$

Suma -\frac{27}{8} e \frac{27}{4} para obter \frac{27}{8}.

$$S=\frac{27}{8}+\frac{9}{2}$$

Suma \frac{27}{8} e \frac{9}{2} para obter \frac{63}{8}.

$$S=\frac{63}{8}$$

O sistema xa funciona correctamente.

$$S=\frac{63}{8} m=\frac{3}{2}$$