Resolver 5!/3!(5-3)!*{left(1/4right)}^3*{left(3/4right)}^2

$$\frac{ 5 ! }{ 3 ! (5-3) ! } \times { \left( \frac{ 1 }{ 4 } \right) }^{ 3 } \times { \left( \frac{ 3 }{ 4 } \right) }^{ 2 }$$

Calcular

$$\frac{45}{512}=0.087890625$$

Pasos da solución

O factor de 5 é 120.

$$\frac{120}{3!\left(5-3\right)!}\times \left(\frac{1}{4}\right)^{3}\times \left(\frac{3}{4}\right)^{2}$$

O factor de 3 é 6.

$$\frac{120}{6\left(5-3\right)!}\times \left(\frac{1}{4}\right)^{3}\times \left(\frac{3}{4}\right)^{2}$$

Resta 3 de 5 para obter 2.

$$\frac{120}{6\times 2!}\times \left(\frac{1}{4}\right)^{3}\times \left(\frac{3}{4}\right)^{2}$$

O factor de 2 é 2.

$$\frac{120}{6\times 2}\times \left(\frac{1}{4}\right)^{3}\times \left(\frac{3}{4}\right)^{2}$$

Multiplica 6 e 2 para obter 12.

$$\frac{120}{12}\times \left(\frac{1}{4}\right)^{3}\times \left(\frac{3}{4}\right)^{2}$$

Divide 120 entre 12 para obter 10.

$$10\times \left(\frac{1}{4}\right)^{3}\times \left(\frac{3}{4}\right)^{2}$$

Calcula \frac{1}{4} á potencia de 3 e obtén \frac{1}{64}.

$$10\times \frac{1}{64}\times \left(\frac{3}{4}\right)^{2}$$

Multiplica 10 e \frac{1}{64} para obter \frac{10}{64}.

$$\frac{10}{64}\times \left(\frac{3}{4}\right)^{2}$$

Reduce a fracción \frac{10}{64} a termos máis baixos extraendo e cancelando 2.

$$\frac{5}{32}\times \left(\frac{3}{4}\right)^{2}$$

Calcula \frac{3}{4} á potencia de 2 e obtén \frac{9}{16}.

$$\frac{5}{32}\times \frac{9}{16}$$

Multiplica \frac{5}{32} por \frac{9}{16} mediante a multiplicación do numerador polo numerador e do denominador polo denominador.

$$\frac{5\times 9}{32\times 16}$$

Fai as multiplicacións na fracción \frac{5\times 9}{32\times 16}.

$$\frac{45}{512}$$

Factorizar

$$\frac{3 ^ {2} \cdot 5}{2 ^ {9}} = 0.087890625$$