Resolver left(7-2right)^2*2+4/sqrt{64+3*4}div27/10

$$\frac{ { \left(7-2 \right) }^{ 2 } \times 2+4 }{ \sqrt{ 64 } +3 \times 4 } \div \frac{ 27 }{ 10 }$$

Calcular

$$1$$

Pasos da solución

Divide \frac{\left(7-2\right)^{2}\times 2+4}{\sqrt{64}+3\times 4} entre \frac{27}{10} mediante a multiplicación de \frac{\left(7-2\right)^{2}\times 2+4}{\sqrt{64}+3\times 4} polo recíproco de \frac{27}{10}.

$$\frac{\left(\left(7-2\right)^{2}\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Resta 2 de 7 para obter 5.

$$\frac{\left(5^{2}\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Calcula 5 á potencia de 2 e obtén 25.

$$\frac{\left(25\times 2+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Multiplica 25 e 2 para obter 50.

$$\frac{\left(50+4\right)\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Suma 50 e 4 para obter 54.

$$\frac{54\times 10}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Multiplica 54 e 10 para obter 540.

$$\frac{540}{\left(\sqrt{64}+3\times 4\right)\times 27}$$

Calcular a raíz cadrada de 64 e obter 8.

$$\frac{540}{\left(8+3\times 4\right)\times 27}$$

Multiplica 3 e 4 para obter 12.

$$\frac{540}{\left(8+12\right)\times 27}$$

Suma 8 e 12 para obter 20.

$$\frac{540}{20\times 27}$$

Multiplica 20 e 27 para obter 540.

$$\frac{540}{540}$$

Divide 540 entre 540 para obter 1.

$$1$$

Factorizar

$$1$$