Resolver tan(215)+tan(145)/tan(305)+tan(35)

$$\frac{ \tan ( 215 ) + \tan ( 145 ) }{ \tan ( 305 ) + \tan ( 35 ) }$$

Calcular

$$\frac{10}{7279404685324049}\approx 1.37373871 \cdot 10^{-15}$$

Pasos da solución

Evaluate trigonometric functions in the problem

$$\frac{0.7002075382097092 + -0.7002075382097102}{-1.4281480067421146 + 0.7002075382097097}$$

Resta 0.7002075382097102 de 0.7002075382097092 para obter -0.000000000000001.

$$\frac{-0.000000000000001}{-1.4281480067421146+0.7002075382097097}$$

Suma -1.4281480067421146 e 0.7002075382097097 para obter -0.7279404685324049.

$$\frac{-0.000000000000001}{-0.7279404685324049}$$

Expande \frac{-0.000000000000001}{-0.7279404685324049} multiplicando o numerador e o denominador por 10000000000000000.

$$\frac{-10}{-7279404685324049}$$

A fracción \frac{-10}{-7279404685324049} pode simplificarse a \frac{10}{7279404685324049} quitando o signo negativo do numerador e do denominador.

$$\frac{10}{7279404685324049}$$

Factorizar

$$\frac{2 \cdot 5}{17 \cdot 5639 \cdot 75935498423} = 1.3737387097273108 \times 10^{-15}$$