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\frac{\frac{\left(-\frac{1}{6}\right)^{2}}{\frac{5}{6}}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Resta \frac{2}{3} de \frac{1}{2} para obter -\frac{1}{6}.
\frac{\frac{\frac{1}{36}}{\frac{5}{6}}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Calcula -\frac{1}{6} á potencia de 2 e obtén \frac{1}{36}.
\frac{\frac{1}{36}\times \frac{6}{5}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Divide \frac{1}{36} entre \frac{5}{6} mediante a multiplicación de \frac{1}{36} polo recíproco de \frac{5}{6}.
\frac{\frac{1}{30}-\sqrt{\frac{1}{9}}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Multiplica \frac{1}{36} e \frac{6}{5} para obter \frac{1}{30}.
\frac{\frac{1}{30}-\frac{1}{3}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Reescribe a raíz cadrada da división \frac{1}{9} como a división de raíces cadradas \frac{\sqrt{1}}{\sqrt{9}}. Obtén a raíz cadrada do numerador e o denominador.
\frac{-\frac{3}{10}}{\sqrt[3]{\frac{1}{8}}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Resta \frac{1}{3} de \frac{1}{30} para obter -\frac{3}{10}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\left(1-\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Calcular \sqrt[3]{\frac{1}{8}} e obter \frac{1}{2}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\left(\frac{1}{2}\right)^{2}\times \frac{9}{8}}
Resta \frac{1}{2} de 1 para obter \frac{1}{2}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\frac{1}{4}\times \frac{9}{8}}
Calcula \frac{1}{2} á potencia de 2 e obtén \frac{1}{4}.
\frac{-\frac{3}{10}}{\frac{1}{2}+\frac{9}{32}}
Multiplica \frac{1}{4} e \frac{9}{8} para obter \frac{9}{32}.
\frac{-\frac{3}{10}}{\frac{25}{32}}
Suma \frac{1}{2} e \frac{9}{32} para obter \frac{25}{32}.
-\frac{3}{10}\times \frac{32}{25}
Divide -\frac{3}{10} entre \frac{25}{32} mediante a multiplicación de -\frac{3}{10} polo recíproco de \frac{25}{32}.
-\frac{48}{125}
Multiplica -\frac{3}{10} e \frac{32}{25} para obter -\frac{48}{125}.