Resolver 7/4-sqrt[3]{(3/2)^2+2^-1+1}=

$$\frac { 7 } { 4 } - \sqrt[ 3 ] { ( \frac { 3 } { 2 } ) ^ { 2 } + 2 ^ { - 1 } + 1 } =$$

Calcular

$$-\frac{\sqrt[3]{30}}{2}+\frac{7}{4}\approx 0.196383747$$

Pasos da solución

Calcula \frac{3}{2} á potencia de 2 e obtén \frac{9}{4}.

$$\frac{7}{4}-\sqrt[3]{\frac{9}{4}+2^{-1}+1}$$

Calcula 2 á potencia de -1 e obtén \frac{1}{2}.

$$\frac{7}{4}-\sqrt[3]{\frac{9}{4}+\frac{1}{2}+1}$$

Suma \frac{9}{4} e \frac{1}{2} para obter \frac{11}{4}.

$$\frac{7}{4}-\sqrt[3]{\frac{11}{4}+1}$$

Suma \frac{11}{4} e 1 para obter \frac{15}{4}.

$$\frac{7}{4}-\sqrt[3]{\frac{15}{4}}$$

Factorizar

$$\frac{7 - 2 \sqrt[3]{30}}{4} = 0.1963837470230707$$