Resolver 3.14*0.05*(30/2-2)/3((30/2)^2+30*2/2+2^2)

$$\frac { 3.14 \times 0.05 \times ( \frac { 30 } { 2 } - 2 ) } { 3 } ( ( \frac { 30 } { 2 } ) ^ { 2 } + \frac { 30 \times 2 } { 2 } + 2 ^ { 2 } )$$

Calcular

$$\frac{528619}{3000}\approx 176.206333333$$

Pasos da solución

Multiplica 3.14 e 0.05 para obter 0.157.

$$\frac{0.157\left(\frac{30}{2}-2\right)}{3}\left(\left(\frac{30}{2}\right)^{2}+\frac{30\times 2}{2}+2^{2}\right)$$

Divide 30 entre 2 para obter 15.

$$\frac{0.157\left(15-2\right)}{3}\left(\left(\frac{30}{2}\right)^{2}+\frac{30\times 2}{2}+2^{2}\right)$$

Resta 2 de 15 para obter 13.

$$\frac{0.157\times 13}{3}\left(\left(\frac{30}{2}\right)^{2}+\frac{30\times 2}{2}+2^{2}\right)$$

Multiplica 0.157 e 13 para obter 2.041.

$$\frac{2.041}{3}\left(\left(\frac{30}{2}\right)^{2}+\frac{30\times 2}{2}+2^{2}\right)$$

Expande \frac{2.041}{3} multiplicando o numerador e o denominador por 1000.

$$\frac{2041}{3000}\left(\left(\frac{30}{2}\right)^{2}+\frac{30\times 2}{2}+2^{2}\right)$$

Divide 30 entre 2 para obter 15.

$$\frac{2041}{3000}\left(15^{2}+\frac{30\times 2}{2}+2^{2}\right)$$

Calcula 15 á potencia de 2 e obtén 225.

$$\frac{2041}{3000}\left(225+\frac{30\times 2}{2}+2^{2}\right)$$

Anula 2 e 2.

$$\frac{2041}{3000}\left(225+30+2^{2}\right)$$

Suma 225 e 30 para obter 255.

$$\frac{2041}{3000}\left(255+2^{2}\right)$$

Calcula 2 á potencia de 2 e obtén 4.

$$\frac{2041}{3000}\left(255+4\right)$$

Suma 255 e 4 para obter 259.

$$\frac{2041}{3000}\times 259$$

Multiplica \frac{2041}{3000} e 259 para obter \frac{528619}{3000}.

$$\frac{528619}{3000}$$

Factorizar

$$\frac{7 \cdot 13 \cdot 37 \cdot 157}{3 \cdot 2 ^ {3} \cdot 5 ^ {3}} = 176\frac{619}{3000} = 176.20633333333333$$