Resolver 3^-2(frac{1/5)^-3sqrt[3]{27}}{3-1/3-2*(-1/2+1)}=

$$\frac { 3 ^ { - 2 } ( \frac { 1 } { 5 } ) ^ { - 3 } \sqrt[ 3 ] { 27 } } { 3 - \frac { 1 } { 3 } - 2 \cdot ( - \frac { 1 } { 2 } + 1 ) } =$$

Calcular

$$25$$

Pasos da solución

Calcula 3 á potencia de -2 e obtén \frac{1}{9}.

$$\frac{\frac{1}{9}\times \left(\frac{1}{5}\right)^{-3}\sqrt[3]{27}}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Calcula \frac{1}{5} á potencia de -3 e obtén 125.

$$\frac{\frac{1}{9}\times 125\sqrt[3]{27}}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Multiplica \frac{1}{9} e 125 para obter \frac{125}{9}.

$$\frac{\frac{125}{9}\sqrt[3]{27}}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Calcular \sqrt[3]{27} e obter 3.

$$\frac{\frac{125}{9}\times 3}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Multiplica \frac{125}{9} e 3 para obter \frac{125}{3}.

$$\frac{\frac{125}{3}}{3-\frac{1}{3}-2\left(-\frac{1}{2}+1\right)}$$

Resta \frac{1}{3} de 3 para obter \frac{8}{3}.

$$\frac{\frac{125}{3}}{\frac{8}{3}-2\left(-\frac{1}{2}+1\right)}$$

Suma -\frac{1}{2} e 1 para obter \frac{1}{2}.

$$\frac{\frac{125}{3}}{\frac{8}{3}-2\times \frac{1}{2}}$$

Multiplica 2 e \frac{1}{2} para obter 1.

$$\frac{\frac{125}{3}}{\frac{8}{3}-1}$$

Resta 1 de \frac{8}{3} para obter \frac{5}{3}.

$$\frac{\frac{125}{3}}{\frac{5}{3}}$$

Divide \frac{125}{3} entre \frac{5}{3} mediante a multiplicación de \frac{125}{3} polo recíproco de \frac{5}{3}.

$$\frac{125}{3}\times \frac{3}{5}$$

Multiplica \frac{125}{3} e \frac{3}{5} para obter 25.

$$25$$

Factorizar

$$5^{2}$$