Resolver 11/7:[(-3/2)^-1-(4/3-2)^2*(3/7-frac{3}{4})]

$$\frac { 11 } { 7 } : [ ( - \frac { 3 } { 2 } ) ^ { - 1 } - ( \frac { 4 } { 3 } - 2 ) ^ { 2 } \cdot ( \frac { 3 } { 7 } - \frac { 3 } { 4 } ) ]$$

Calcular

$$-3$$

Pasos da solución

Calcula -\frac{3}{2} á potencia de -1 e obtén -\frac{2}{3}.

$$\frac{\frac{11}{7}}{-\frac{2}{3}-\left(\frac{4}{3}-2\right)^{2}\left(\frac{3}{7}-\frac{3}{4}\right)}$$

Resta 2 de \frac{4}{3} para obter -\frac{2}{3}.

$$\frac{\frac{11}{7}}{-\frac{2}{3}-\left(-\frac{2}{3}\right)^{2}\left(\frac{3}{7}-\frac{3}{4}\right)}$$

Calcula -\frac{2}{3} á potencia de 2 e obtén \frac{4}{9}.

$$\frac{\frac{11}{7}}{-\frac{2}{3}-\frac{4}{9}\left(\frac{3}{7}-\frac{3}{4}\right)}$$

Resta \frac{3}{4} de \frac{3}{7} para obter -\frac{9}{28}.

$$\frac{\frac{11}{7}}{-\frac{2}{3}-\frac{4}{9}\left(-\frac{9}{28}\right)}$$

Multiplica \frac{4}{9} e -\frac{9}{28} para obter -\frac{1}{7}.

$$\frac{\frac{11}{7}}{-\frac{2}{3}-\left(-\frac{1}{7}\right)}$$

O contrario de -\frac{1}{7} é \frac{1}{7}.

$$\frac{\frac{11}{7}}{-\frac{2}{3}+\frac{1}{7}}$$

Suma -\frac{2}{3} e \frac{1}{7} para obter -\frac{11}{21}.

$$\frac{\frac{11}{7}}{-\frac{11}{21}}$$

Divide \frac{11}{7} entre -\frac{11}{21} mediante a multiplicación de \frac{11}{7} polo recíproco de -\frac{11}{21}.

$$\frac{11}{7}\left(-\frac{21}{11}\right)$$

Multiplica \frac{11}{7} e -\frac{21}{11} para obter -3.

$$-3$$

Factorizar

$$-3$$