Resolver 1/3*22/7*14[(35/2)^2+(38^2/2)^2+(frac{35}{2}*frac{30}{2})]

$$\frac { 1 } { 3 } \times \frac { 22 } { 7 } \times 14 [ ( \frac { 35 } { 2 } ) ^ { 2 } + ( \frac { 38 ^ { 2 } } { 2 } ) ^ { 2 } + ( \frac { 35 } { 2 } \times \frac { 30 } { 2 } ) ]$$

Calcular

$$\frac{22961521}{3}\approx 7653840.333333333$$

Pasos da solución

Multiplica \frac{1}{3} e \frac{22}{7} para obter \frac{22}{21}.

$$\frac{22}{21}\times 14\left(\left(\frac{35}{2}\right)^{2}+\left(\frac{38^{2}}{2}\right)^{2}+\frac{35}{2}\times \frac{30}{2}\right)$$

Multiplica \frac{22}{21} e 14 para obter \frac{44}{3}.

$$\frac{44}{3}\left(\left(\frac{35}{2}\right)^{2}+\left(\frac{38^{2}}{2}\right)^{2}+\frac{35}{2}\times \frac{30}{2}\right)$$

Calcula \frac{35}{2} á potencia de 2 e obtén \frac{1225}{4}.

$$\frac{44}{3}\left(\frac{1225}{4}+\left(\frac{38^{2}}{2}\right)^{2}+\frac{35}{2}\times \frac{30}{2}\right)$$

Calcula 38 á potencia de 2 e obtén 1444.

$$\frac{44}{3}\left(\frac{1225}{4}+\left(\frac{1444}{2}\right)^{2}+\frac{35}{2}\times \frac{30}{2}\right)$$

Divide 1444 entre 2 para obter 722.

$$\frac{44}{3}\left(\frac{1225}{4}+722^{2}+\frac{35}{2}\times \frac{30}{2}\right)$$

Calcula 722 á potencia de 2 e obtén 521284.

$$\frac{44}{3}\left(\frac{1225}{4}+521284+\frac{35}{2}\times \frac{30}{2}\right)$$

Suma \frac{1225}{4} e 521284 para obter \frac{2086361}{4}.

$$\frac{44}{3}\left(\frac{2086361}{4}+\frac{35}{2}\times \frac{30}{2}\right)$$

Divide 30 entre 2 para obter 15.

$$\frac{44}{3}\left(\frac{2086361}{4}+\frac{35}{2}\times 15\right)$$

Multiplica \frac{35}{2} e 15 para obter \frac{525}{2}.

$$\frac{44}{3}\left(\frac{2086361}{4}+\frac{525}{2}\right)$$

Suma \frac{2086361}{4} e \frac{525}{2} para obter \frac{2087411}{4}.

$$\frac{44}{3}\times \frac{2087411}{4}$$

Multiplica \frac{44}{3} e \frac{2087411}{4} para obter \frac{22961521}{3}.

$$\frac{22961521}{3}$$

Factorizar

$$\frac{11 \cdot 23 \cdot 47 \cdot 1931}{3} = 7653840\frac{1}{3} = 7653840.333333333$$