Resolver frac{(9*10^{9})*(4.5*10^-6)*(5*10^-6)}{(15*10^-2)^2}

$$\frac { ( 9 \times 10 ^ { 9 } ) \times ( 4.5 \times 10 ^ { - 6 } ) \times ( 5 \times 10 ^ { - 6 } ) } { ( 15 \times 10 ^ { - 2 } ) ^ { 2 } }$$

Calcular

$$9$$

Pasos da solución

Para multiplicar potencias da mesma base, suma os seus expoñentes. Suma 9 e -6 para obter 3.

$$\frac{9\times 10^{3}\times 4.5\times 5\times 10^{-6}}{\left(15\times 10^{-2}\right)^{2}}$$

Para multiplicar potencias da mesma base, suma os seus expoñentes. Suma 3 e -6 para obter -3.

$$\frac{9\times 10^{-3}\times 4.5\times 5}{\left(15\times 10^{-2}\right)^{2}}$$

Calcula 10 á potencia de -3 e obtén \frac{1}{1000}.

$$\frac{9\times \frac{1}{1000}\times 4.5\times 5}{\left(15\times 10^{-2}\right)^{2}}$$

Multiplica 9 e \frac{1}{1000} para obter \frac{9}{1000}.

$$\frac{\frac{9}{1000}\times 4.5\times 5}{\left(15\times 10^{-2}\right)^{2}}$$

Multiplica \frac{9}{1000} e 4.5 para obter \frac{81}{2000}.

$$\frac{\frac{81}{2000}\times 5}{\left(15\times 10^{-2}\right)^{2}}$$

Multiplica \frac{81}{2000} e 5 para obter \frac{81}{400}.

$$\frac{\frac{81}{400}}{\left(15\times 10^{-2}\right)^{2}}$$

Calcula 10 á potencia de -2 e obtén \frac{1}{100}.

$$\frac{\frac{81}{400}}{\left(15\times \frac{1}{100}\right)^{2}}$$

Multiplica 15 e \frac{1}{100} para obter \frac{3}{20}.

$$\frac{\frac{81}{400}}{\left(\frac{3}{20}\right)^{2}}$$

Calcula \frac{3}{20} á potencia de 2 e obtén \frac{9}{400}.

$$\frac{\frac{81}{400}}{\frac{9}{400}}$$

Divide \frac{81}{400} entre \frac{9}{400} mediante a multiplicación de \frac{81}{400} polo recíproco de \frac{9}{400}.

$$\frac{81}{400}\times \frac{400}{9}$$

Multiplica \frac{81}{400} e \frac{400}{9} para obter 9.

$$9$$

Factorizar

$$3^{2}$$