Resolver (5.3)^4+4*(49)^4/(5.3)^2+2(4.9)^2+51.94=?

$$\frac { ( 5.3 ) ^ { 4 } + 4 * ( 49 ) ^ { 4 } } { ( 5.3 ) ^ { 2 } + 2 ( 4.9 ) ^ { 2 } + 51.94 } = ?$$

Calcular

$$\frac{230599930481}{1280500}\approx 180085.84965326$$

Pasos da solución

Calcula 5.3 á potencia de 4 e obtén 789.0481.

$$\frac{789.0481+4\times 49^{4}}{5.3^{2}+2\times 4.9^{2}+51.94}$$

Calcula 49 á potencia de 4 e obtén 5764801.

$$\frac{789.0481+4\times 5764801}{5.3^{2}+2\times 4.9^{2}+51.94}$$

Multiplica 4 e 5764801 para obter 23059204.

$$\frac{789.0481+23059204}{5.3^{2}+2\times 4.9^{2}+51.94}$$

Suma 789.0481 e 23059204 para obter 23059993.0481.

$$\frac{23059993.0481}{5.3^{2}+2\times 4.9^{2}+51.94}$$

Calcula 5.3 á potencia de 2 e obtén 28.09.

$$\frac{23059993.0481}{28.09+2\times 4.9^{2}+51.94}$$

Calcula 4.9 á potencia de 2 e obtén 24.01.

$$\frac{23059993.0481}{28.09+2\times 24.01+51.94}$$

Multiplica 2 e 24.01 para obter 48.02.

$$\frac{23059993.0481}{28.09+48.02+51.94}$$

Suma 28.09 e 48.02 para obter 76.11.

$$\frac{23059993.0481}{76.11+51.94}$$

Suma 76.11 e 51.94 para obter 128.05.

$$\frac{23059993.0481}{128.05}$$

Expande \frac{23059993.0481}{128.05} multiplicando o numerador e o denominador por 10000.

$$\frac{230599930481}{1280500}$$

Factorizar

$$\frac{17 \cdot 25357 \cdot 534949}{13 \cdot 197 \cdot 2 ^ {2} \cdot 5 ^ {3}} = 180085\frac{1087981}{1280500} = 180085.84965326043$$