Resolver (-5)^2-3^2+(2/3)^0/3^-2+frac{1{5}+1/2}

$$\frac { ( - 5 ) ^ { 2 } - 3 ^ { 2 } + ( \frac { 2 } { 3 } ) ^ { 0 } } { 3 ^ { - 2 } + \frac { 1 } { 5 } + \frac { 1 } { 2 } }$$

Calcular

$$\frac{1530}{73}\approx 20.95890411$$

Pasos da solución

Calcula -5 á potencia de 2 e obtén 25.

$$\frac{25-3^{2}+\left(\frac{2}{3}\right)^{0}}{3^{-2}+\frac{1}{5}+\frac{1}{2}}$$

Calcula 3 á potencia de 2 e obtén 9.

$$\frac{25-9+\left(\frac{2}{3}\right)^{0}}{3^{-2}+\frac{1}{5}+\frac{1}{2}}$$

Resta 9 de 25 para obter 16.

$$\frac{16+\left(\frac{2}{3}\right)^{0}}{3^{-2}+\frac{1}{5}+\frac{1}{2}}$$

Calcula \frac{2}{3} á potencia de 0 e obtén 1.

$$\frac{16+1}{3^{-2}+\frac{1}{5}+\frac{1}{2}}$$

Suma 16 e 1 para obter 17.

$$\frac{17}{3^{-2}+\frac{1}{5}+\frac{1}{2}}$$

Calcula 3 á potencia de -2 e obtén \frac{1}{9}.

$$\frac{17}{\frac{1}{9}+\frac{1}{5}+\frac{1}{2}}$$

Suma \frac{1}{9} e \frac{1}{5} para obter \frac{14}{45}.

$$\frac{17}{\frac{14}{45}+\frac{1}{2}}$$

Suma \frac{14}{45} e \frac{1}{2} para obter \frac{73}{90}.

$$\frac{17}{\frac{73}{90}}$$

Divide 17 entre \frac{73}{90} mediante a multiplicación de 17 polo recíproco de \frac{73}{90}.

$$17\times \frac{90}{73}$$

Multiplica 17 e \frac{90}{73} para obter \frac{1530}{73}.

$$\frac{1530}{73}$$

Factorizar

$$\frac{2 \cdot 3 ^ {2} \cdot 5 \cdot 17}{73} = 20\frac{70}{73} = 20.958904109589042$$