Resolver (1/3+frac{7/9)^{2}}{(1-1/2)^2(-2)^3-3/2}+(-frac{1}{6})^2+frac{frac{1}{4}-frac{1}{5}}{(1-frac{2}{5})^2}|-frac{frac{1}{3}-frac{2}{9}}{frac{1}{8}-frac{15}{8}}=

$$\frac { ( \frac { 1 } { 3 } + \frac { 7 } { 9 } ) ^ { 2 } } { ( 1 - \frac { 1 } { 2 } ) ^ { 2 } ( - 2 ) ^ { 3 } - \frac { 3 } { 2 } } + ( - \frac { 1 } { 6 } ) ^ { 2 } + \frac { \frac { 1 } { 4 } - \frac { 1 } { 5 } } { ( 1 - \frac { 2 } { 5 } ) ^ { 2 } } | - \frac { \frac { 1 } { 3 } - \frac { 2 } { 9 } } { \frac { 1 } { 8 } - \frac { 15 } { 8 } } =$$

Calcular

$$-\frac{239}{756}\approx -0.316137566$$

Pasos da solución

Suma \frac{1}{3} e \frac{7}{9} para obter \frac{10}{9}.

$$\frac{\left(\frac{10}{9}\right)^{2}}{\left(1-\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calcula \frac{10}{9} á potencia de 2 e obtén \frac{100}{81}.

$$\frac{\frac{100}{81}}{\left(1-\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Resta \frac{1}{2} de 1 para obter \frac{1}{2}.

$$\frac{\frac{100}{81}}{\left(\frac{1}{2}\right)^{2}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calcula \frac{1}{2} á potencia de 2 e obtén \frac{1}{4}.

$$\frac{\frac{100}{81}}{\frac{1}{4}\left(-2\right)^{3}-\frac{3}{2}}+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calcula -2 á potencia de 3 e obtén -8.

$$\frac{\frac{100}{81}}{\frac{1}{4}\left(-8\right)-\frac{3}{2}}+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Multiplica \frac{1}{4} e -8 para obter -2.

$$\frac{\frac{100}{81}}{-2-\frac{3}{2}}+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Resta \frac{3}{2} de -2 para obter -\frac{7}{2}.

$$\frac{\frac{100}{81}}{-\frac{7}{2}}+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Divide \frac{100}{81} entre -\frac{7}{2} mediante a multiplicación de \frac{100}{81} polo recíproco de -\frac{7}{2}.

$$\frac{100}{81}\left(-\frac{2}{7}\right)+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Multiplica \frac{100}{81} e -\frac{2}{7} para obter -\frac{200}{567}.

$$-\frac{200}{567}+\left(-\frac{1}{6}\right)^{2}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calcula -\frac{1}{6} á potencia de 2 e obtén \frac{1}{36}.

$$-\frac{200}{567}+\frac{1}{36}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Suma -\frac{200}{567} e \frac{1}{36} para obter -\frac{737}{2268}.

$$-\frac{737}{2268}+\frac{\frac{1}{4}-\frac{1}{5}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Resta \frac{1}{5} de \frac{1}{4} para obter \frac{1}{20}.

$$-\frac{737}{2268}+\frac{\frac{1}{20}}{\left(1-\frac{2}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Resta \frac{2}{5} de 1 para obter \frac{3}{5}.

$$-\frac{737}{2268}+\frac{\frac{1}{20}}{\left(\frac{3}{5}\right)^{2}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Calcula \frac{3}{5} á potencia de 2 e obtén \frac{9}{25}.

$$-\frac{737}{2268}+\frac{\frac{1}{20}}{\frac{9}{25}}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Divide \frac{1}{20} entre \frac{9}{25} mediante a multiplicación de \frac{1}{20} polo recíproco de \frac{9}{25}.

$$-\frac{737}{2268}+\frac{1}{20}\times \frac{25}{9}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Multiplica \frac{1}{20} e \frac{25}{9} para obter \frac{5}{36}.

$$-\frac{737}{2268}+\frac{5}{36}|-\frac{\frac{1}{3}-\frac{2}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Resta \frac{2}{9} de \frac{1}{3} para obter \frac{1}{9}.

$$-\frac{737}{2268}+\frac{5}{36}|-\frac{\frac{1}{9}}{\frac{1}{8}-\frac{15}{8}}|$$

Resta \frac{15}{8} de \frac{1}{8} para obter -\frac{7}{4}.

$$-\frac{737}{2268}+\frac{5}{36}|-\frac{\frac{1}{9}}{-\frac{7}{4}}|$$

Divide \frac{1}{9} entre -\frac{7}{4} mediante a multiplicación de \frac{1}{9} polo recíproco de -\frac{7}{4}.

$$-\frac{737}{2268}+\frac{5}{36}|-\frac{1}{9}\left(-\frac{4}{7}\right)|$$

Multiplica \frac{1}{9} e -\frac{4}{7} para obter -\frac{4}{63}.

$$-\frac{737}{2268}+\frac{5}{36}|-\left(-\frac{4}{63}\right)|$$

O contrario de -\frac{4}{63} é \frac{4}{63}.

$$-\frac{737}{2268}+\frac{5}{36}|\frac{4}{63}|$$

O valor absoluto dun número real a é a cando a\geq 0 ou -a cando a<0. O valor absoluto de \frac{4}{63} é \frac{4}{63}.

$$-\frac{737}{2268}+\frac{5}{36}\times \frac{4}{63}$$

Multiplica \frac{5}{36} e \frac{4}{63} para obter \frac{5}{567}.

$$-\frac{737}{2268}+\frac{5}{567}$$

Suma -\frac{737}{2268} e \frac{5}{567} para obter -\frac{239}{756}.

$$-\frac{239}{756}$$

Factorizar

$$-\frac{239}{756} = -0.31613756613756616$$