Resolver {(1/3)^-2-(1/2)^-3}(1/4)^2

$$\{ ( \frac { 1 } { 3 } ) ^ { - 2 } - ( \frac { 1 } { 2 } ) ^ { - 3 } \} ( \frac { 1 } { 4 } ) ^ { 2 }$$

Calcular

$$\frac{1}{16}=0.0625$$

Pasos da solución

Calcula \frac{1}{3} á potencia de -2 e obtén 9.

$$\left(9-\left(\frac{1}{2}\right)^{-3}\right)\times \left(\frac{1}{4}\right)^{2}$$

Calcula \frac{1}{2} á potencia de -3 e obtén 8.

$$\left(9-8\right)\times \left(\frac{1}{4}\right)^{2}$$

Resta 8 de 9 para obter 1.

$$1\times \left(\frac{1}{4}\right)^{2}$$

Calcula \frac{1}{4} á potencia de 2 e obtén \frac{1}{16}.

$$1\times \frac{1}{16}$$

Multiplica 1 e \frac{1}{16} para obter \frac{1}{16}.

$$\frac{1}{16}$$

Factorizar

$$\frac{1}{2 ^ {4}} = 0.0625$$