Resolver [3^3*2^2-4*(27-23)/2]+(12/4)^2=109

$$[ 3 ^ { 3 } \cdot 2 ^ { 2 } - 4 \cdot \frac { ( 27 - 23 ) } { 2 } ] + ( \frac { 12 } { 4 } ) ^ { 2 } = 109$$

Verificar

Pasos da solución

Multiplica ambos lados da ecuación por 2.

$$2\left(3^{3}\times 2^{2}-4\times \frac{27-23}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Calcula 3 á potencia de 3 e obtén 27.

$$2\left(27\times 2^{2}-4\times \frac{27-23}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Calcula 2 á potencia de 2 e obtén 4.

$$2\left(27\times 4-4\times \frac{27-23}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Multiplica 27 e 4 para obter 108.

$$2\left(108-4\times \frac{27-23}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Resta 23 de 27 para obter 4.

$$2\left(108-4\times \frac{4}{2}\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Divide 4 entre 2 para obter 2.

$$2\left(108-4\times 2\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Multiplica 4 e 2 para obter 8.

$$2\left(108-8\right)+2\times \left(\frac{12}{4}\right)^{2}=218$$

Resta 8 de 108 para obter 100.

$$2\times 100+2\times \left(\frac{12}{4}\right)^{2}=218$$

Multiplica 2 e 100 para obter 200.

$$200+2\times \left(\frac{12}{4}\right)^{2}=218$$

Divide 12 entre 4 para obter 3.

$$200+2\times 3^{2}=218$$

Calcula 3 á potencia de 2 e obtén 9.

$$200+2\times 9=218$$

Multiplica 2 e 9 para obter 18.

$$200+18=218$$

Suma 200 e 18 para obter 218.

$$218=218$$

Comparar 218 e 218.

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