Resolver [15-(-34+12)-(-3)]*(12div4)*(12-4)]-(15*8)

$$[ 15 - ( - 34 + 12 ) - ( - 3 ) ] \cdot ( 12 \div 4 ) \cdot ( 12 - 4 ) ] - ( 15 \cdot 8 )$$

Calcular

$$960$$

Pasos da solución

Suma -34 e 12 para obter -22.

$$\left(15-\left(-22\right)-\left(-3\right)\right)\times \frac{12}{4}\left(12-4\right)$$

O contrario de -22 é 22.

$$\left(15+22-\left(-3\right)\right)\times \frac{12}{4}\left(12-4\right)$$

Suma 15 e 22 para obter 37.

$$\left(37-\left(-3\right)\right)\times \frac{12}{4}\left(12-4\right)$$

O contrario de -3 é 3.

$$\left(37+3\right)\times \frac{12}{4}\left(12-4\right)$$

Suma 37 e 3 para obter 40.

$$40\times \frac{12}{4}\left(12-4\right)$$

Divide 12 entre 4 para obter 3.

$$40\times 3\left(12-4\right)$$

Multiplica 40 e 3 para obter 120.

$$120\left(12-4\right)$$

Resta 4 de 12 para obter 8.

$$120\times 8$$

Multiplica 120 e 8 para obter 960.

$$960$$

Factorizar

$$2^{6}\times 3\times 5$$