Resolver [(1-1/3)^2+(1-1/9)]:(2-1/3)=

$$[ ( 1 - \frac { 1 } { 3 } ) ^ { 2 } + ( 1 - \frac { 1 } { 9 } ) ] : ( 2 - \frac { 1 } { 3 } ) =$$

Calcular

$$\frac{4}{5}=0.8$$

Pasos da solución

Resta \frac{1}{3} de 1 para obter \frac{2}{3}.

$$\frac{\left(\frac{2}{3}\right)^{2}+1-\frac{1}{9}}{2-\frac{1}{3}}$$

Calcula \frac{2}{3} á potencia de 2 e obtén \frac{4}{9}.

$$\frac{\frac{4}{9}+1-\frac{1}{9}}{2-\frac{1}{3}}$$

Suma \frac{4}{9} e 1 para obter \frac{13}{9}.

$$\frac{\frac{13}{9}-\frac{1}{9}}{2-\frac{1}{3}}$$

Resta \frac{1}{9} de \frac{13}{9} para obter \frac{4}{3}.

$$\frac{\frac{4}{3}}{2-\frac{1}{3}}$$

Resta \frac{1}{3} de 2 para obter \frac{5}{3}.

$$\frac{\frac{4}{3}}{\frac{5}{3}}$$

Divide \frac{4}{3} entre \frac{5}{3} mediante a multiplicación de \frac{4}{3} polo recíproco de \frac{5}{3}.

$$\frac{4}{3}\times \frac{3}{5}$$

Multiplica \frac{4}{3} e \frac{3}{5} para obter \frac{4}{5}.

$$\frac{4}{5}$$

Factorizar

$$\frac{2 ^ {2}}{5} = 0.8$$