Resolver [5/4-(-2+3/4)^2]:(5/4)^2-(-2)^3}:[43/5-(-frac{4}{5})^2*(2-frac{3}{4})]

$$[ \frac { 5 } { 4 } - ( - 2 + \frac { 3 } { 4 } ) ^ { 2 } ] : ( \frac { 5 } { 4 } ) ^ { 2 } - ( - 2 ) ^ { 3 } \} : [ \frac { 43 } { 5 } - ( - \frac { 4 } { 5 } ) ^ { 2 } \cdot ( 2 - \frac { 3 } { 4 } ) ]$$

Calcular

$$\frac{39}{5}=7.8$$

Pasos da solución

Suma -2 e \frac{3}{4} para obter -\frac{5}{4}.

$$\frac{\frac{5}{4}-\left(-\frac{5}{4}\right)^{2}}{\left(\frac{5}{4}\right)^{2}}-\left(-2\right)^{3}$$

Calcula -\frac{5}{4} á potencia de 2 e obtén \frac{25}{16}.

$$\frac{\frac{5}{4}-\frac{25}{16}}{\left(\frac{5}{4}\right)^{2}}-\left(-2\right)^{3}$$

Resta \frac{25}{16} de \frac{5}{4} para obter -\frac{5}{16}.

$$\frac{-\frac{5}{16}}{\left(\frac{5}{4}\right)^{2}}-\left(-2\right)^{3}$$

Calcula \frac{5}{4} á potencia de 2 e obtén \frac{25}{16}.

$$\frac{-\frac{5}{16}}{\frac{25}{16}}-\left(-2\right)^{3}$$

Divide -\frac{5}{16} entre \frac{25}{16} mediante a multiplicación de -\frac{5}{16} polo recíproco de \frac{25}{16}.

$$-\frac{5}{16}\times \frac{16}{25}-\left(-2\right)^{3}$$

Multiplica -\frac{5}{16} e \frac{16}{25} para obter -\frac{1}{5}.

$$-\frac{1}{5}-\left(-2\right)^{3}$$

Calcula -2 á potencia de 3 e obtén -8.

$$-\frac{1}{5}-\left(-8\right)$$

O contrario de -8 é 8.

$$-\frac{1}{5}+8$$

Suma -\frac{1}{5} e 8 para obter \frac{39}{5}.

$$\frac{39}{5}$$

Factorizar

$$\frac{3 \cdot 13}{5} = 7\frac{4}{5} = 7.8$$