Resolver =(-2-0)^2*4/9+(0-0)^2*3/9+(1-0)^2*2/9

$$= ( - 2 - 0 ) ^ { 2 } \times \frac { 4 } { 9 } + ( 0 - 0 ) ^ { 2 } \times \frac { 3 } { 9 } + ( 1 - 0 ) ^ { 2 } \times \frac { 2 } { 9 }$$

Calcular

$$2$$

Pasos da solución

Resta 0 de -2 para obter -2.

$$\left(-2\right)^{2}\times \frac{4}{9}+\left(0-0\right)^{2}\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Calcula -2 á potencia de 2 e obtén 4.

$$4\times \frac{4}{9}+\left(0-0\right)^{2}\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Multiplica 4 e \frac{4}{9} para obter \frac{16}{9}.

$$\frac{16}{9}+\left(0-0\right)^{2}\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Se restas 0 a si mesmo, quédache 0.

$$\frac{16}{9}+0^{2}\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Calcula 0 á potencia de 2 e obtén 0.

$$\frac{16}{9}+0\times \frac{3}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Reduce a fracción \frac{3}{9} a termos máis baixos extraendo e cancelando 3.

$$\frac{16}{9}+0\times \frac{1}{3}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Multiplica 0 e \frac{1}{3} para obter 0.

$$\frac{16}{9}+0+\left(1-0\right)^{2}\times \frac{2}{9}$$

Suma \frac{16}{9} e 0 para obter \frac{16}{9}.

$$\frac{16}{9}+\left(1-0\right)^{2}\times \frac{2}{9}$$

Resta 0 de 1 para obter 1.

$$\frac{16}{9}+1^{2}\times \frac{2}{9}$$

Calcula 1 á potencia de 2 e obtén 1.

$$\frac{16}{9}+1\times \frac{2}{9}$$

Multiplica 1 e \frac{2}{9} para obter \frac{2}{9}.

$$\frac{16}{9}+\frac{2}{9}$$

Suma \frac{16}{9} e \frac{2}{9} para obter 2.

$$2$$

Factorizar

$$2$$