Réitigh do x. (complex solution)
\left\{\begin{matrix}x=-\frac{8\left(72+4z-y\right)}{8-31y}\text{, }&y\neq \frac{8}{31}\\x\in \mathrm{C}\text{, }&y=\frac{8}{31}\text{ and }z=-\frac{556}{31}\end{matrix}\right.
Réitigh do y. (complex solution)
\left\{\begin{matrix}y=\frac{8\left(x+4z+72\right)}{31x+8}\text{, }&x\neq -\frac{8}{31}\\y\in \mathrm{C}\text{, }&x=-\frac{8}{31}\text{ and }z=-\frac{556}{31}\end{matrix}\right.
Réitigh do x.
\left\{\begin{matrix}x=-\frac{8\left(72+4z-y\right)}{8-31y}\text{, }&y\neq \frac{8}{31}\\x\in \mathrm{R}\text{, }&y=\frac{8}{31}\text{ and }z=-\frac{556}{31}\end{matrix}\right.
Réitigh do y.
\left\{\begin{matrix}y=\frac{8\left(x+4z+72\right)}{31x+8}\text{, }&x\neq -\frac{8}{31}\\y\in \mathrm{R}\text{, }&x=-\frac{8}{31}\text{ and }z=-\frac{556}{31}\end{matrix}\right.
Tráth na gCeist
Linear Equation
5 fadhbanna cosúil le:
y=x+72-93x \div 24y+4z
Roinn
Cóipeáladh go dtí an ghearrthaisce
y=x+72-\frac{31}{8}xy+4z
Roinn 93x faoi 24 chun \frac{31}{8}x a fháil.
x+72-\frac{31}{8}xy+4z=y
Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.
x-\frac{31}{8}xy+4z=y-72
Bain 72 ón dá thaobh.
x-\frac{31}{8}xy=y-72-4z
Bain 4z ón dá thaobh.
\left(1-\frac{31}{8}y\right)x=y-72-4z
Comhcheangail na téarmaí ar fad ina bhfuil x.
\left(-\frac{31y}{8}+1\right)x=y-4z-72
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{\left(-\frac{31y}{8}+1\right)x}{-\frac{31y}{8}+1}=\frac{y-4z-72}{-\frac{31y}{8}+1}
Roinn an dá thaobh faoi 1-\frac{31}{8}y.
x=\frac{y-4z-72}{-\frac{31y}{8}+1}
Má roinntear é faoi 1-\frac{31}{8}y cuirtear an iolrúchán faoi 1-\frac{31}{8}y ar ceal.
x=\frac{8\left(y-4z-72\right)}{8-31y}
Roinn y-72-4z faoi 1-\frac{31}{8}y.
y=x+72-\frac{31}{8}xy+4z
Roinn 93x faoi 24 chun \frac{31}{8}x a fháil.
y+\frac{31}{8}xy=x+72+4z
Cuir \frac{31}{8}xy leis an dá thaobh.
\left(1+\frac{31}{8}x\right)y=x+72+4z
Comhcheangail na téarmaí ar fad ina bhfuil y.
\left(\frac{31x}{8}+1\right)y=x+4z+72
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{\left(\frac{31x}{8}+1\right)y}{\frac{31x}{8}+1}=\frac{x+4z+72}{\frac{31x}{8}+1}
Roinn an dá thaobh faoi 1+\frac{31}{8}x.
y=\frac{x+4z+72}{\frac{31x}{8}+1}
Má roinntear é faoi 1+\frac{31}{8}x cuirtear an iolrúchán faoi 1+\frac{31}{8}x ar ceal.
y=\frac{8\left(x+4z+72\right)}{31x+8}
Roinn x+72+4z faoi 1+\frac{31}{8}x.
y=x+72-\frac{31}{8}xy+4z
Roinn 93x faoi 24 chun \frac{31}{8}x a fháil.
x+72-\frac{31}{8}xy+4z=y
Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.
x-\frac{31}{8}xy+4z=y-72
Bain 72 ón dá thaobh.
x-\frac{31}{8}xy=y-72-4z
Bain 4z ón dá thaobh.
\left(1-\frac{31}{8}y\right)x=y-72-4z
Comhcheangail na téarmaí ar fad ina bhfuil x.
\left(-\frac{31y}{8}+1\right)x=y-4z-72
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{\left(-\frac{31y}{8}+1\right)x}{-\frac{31y}{8}+1}=\frac{y-4z-72}{-\frac{31y}{8}+1}
Roinn an dá thaobh faoi 1-\frac{31}{8}y.
x=\frac{y-4z-72}{-\frac{31y}{8}+1}
Má roinntear é faoi 1-\frac{31}{8}y cuirtear an iolrúchán faoi 1-\frac{31}{8}y ar ceal.
x=\frac{8\left(y-4z-72\right)}{8-31y}
Roinn y-72-4z faoi 1-\frac{31}{8}y.
y=x+72-\frac{31}{8}xy+4z
Roinn 93x faoi 24 chun \frac{31}{8}x a fháil.
y+\frac{31}{8}xy=x+72+4z
Cuir \frac{31}{8}xy leis an dá thaobh.
\left(1+\frac{31}{8}x\right)y=x+72+4z
Comhcheangail na téarmaí ar fad ina bhfuil y.
\left(\frac{31x}{8}+1\right)y=x+4z+72
Tá an chothromóid i bhfoirm chaighdeánach.
\frac{\left(\frac{31x}{8}+1\right)y}{\frac{31x}{8}+1}=\frac{x+4z+72}{\frac{31x}{8}+1}
Roinn an dá thaobh faoi 1+\frac{31}{8}x.
y=\frac{x+4z+72}{\frac{31x}{8}+1}
Má roinntear é faoi 1+\frac{31}{8}x cuirtear an iolrúchán faoi 1+\frac{31}{8}x ar ceal.
y=\frac{8\left(x+4z+72\right)}{31x+8}
Roinn x+72+4z faoi 1+\frac{31}{8}x.
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