Réitigh y^2-8x+6y+1=0

$$y ^ { 2 } - 8 x + 6 y + 1 = 0$$

Réitigh do x.

$$x=\frac{y^{2}+6y+1}{8}$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain y^{2} ón dá thaobh. Is ionann rud ar bith a dhealaítear ó nialas agus a shéanadh.

$$-8x+6y+1=-y^{2}$$

Bain 6y ón dá thaobh.

$$-8x+1=-y^{2}-6y$$

Bain 1 ón dá thaobh.

$$-8x=-y^{2}-6y-1$$

Roinn an dá thaobh faoi -8.

$$\frac{-8x}{-8}=\frac{-y^{2}-6y-1}{-8}$$

Má roinntear é faoi -8 cuirtear an iolrúchán faoi -8 ar ceal.

$$x=\frac{-y^{2}-6y-1}{-8}$$

Roinn -y^{2}-6y-1 faoi -8.

$$x=\frac{y^{2}}{8}+\frac{3y}{4}+\frac{1}{8}$$

Réitigh do y. (complex solution)

$$y=2\sqrt{2\left(x+1\right)}-3$$

$$y=-2\sqrt{2\left(x+1\right)}-3$$

Réitigh do y.

$$y=2\sqrt{2\left(x+1\right)}-3$$

$$y=-2\sqrt{2\left(x+1\right)}-3\text{, }x\geq -1$$