Réitigh t^2-sqrt{3}c-6=0

$$t ^ { 2 } - \sqrt { 3 } c - 6 = 0$$

Réitigh do c.

$$c=\frac{\sqrt{3}\left(t^{2}-6\right)}{3}$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Cuir 6 leis an dá thaobh. Is ionann rud ar bith móide nialas agus a shuim féin.

$$t^{2}-\sqrt{3}c=6$$

Bain t^{2} ón dá thaobh.

$$-\sqrt{3}c=6-t^{2}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(-\sqrt{3}\right)c=6-t^{2}$$

Roinn an dá thaobh faoi -\sqrt{3}.

$$\frac{\left(-\sqrt{3}\right)c}{-\sqrt{3}}=\frac{6-t^{2}}{-\sqrt{3}}$$

Má roinntear é faoi -\sqrt{3} cuirtear an iolrúchán faoi -\sqrt{3} ar ceal.

$$c=\frac{6-t^{2}}{-\sqrt{3}}$$

Roinn 6-t^{2} faoi -\sqrt{3}.

$$c=\frac{\sqrt{3}t^{2}}{3}-2\sqrt{3}$$

Réitigh do t. (complex solution)

$$t=-\sqrt{\sqrt{3}c+6}$$

$$t=\sqrt{\sqrt{3}c+6}$$

Réitigh do t.

$$t=\sqrt{\sqrt{3}c+6}$$

$$t=-\sqrt{\sqrt{3}c+6}\text{, }c\geq -2\sqrt{3}$$