Réitigh s=1/2gt^2+v_{0}t.quadd

$$s = \frac { 1 } { 2 } g t ^ { 2 } + v _ { 0 } t . \quad d$$

Réitigh do g.

$$\left\{\begin{matrix}g=-\frac{2\left(tv_{0}-s\right)}{t^{2}}\text{, }&t\neq 0\\g\in \mathrm{R}\text{, }&s=0\text{ and }t=0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$\frac{1}{2}gt^{2}+v_{0}t=s$$

Bain v_{0}t ón dá thaobh.

$$\frac{1}{2}gt^{2}=s-v_{0}t$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\frac{t^{2}}{2}g=s-tv_{0}$$

Roinn an dá thaobh faoi \frac{1}{2}t^{2}.

$$\frac{2\times \frac{t^{2}}{2}g}{t^{2}}=\frac{2\left(s-tv_{0}\right)}{t^{2}}$$

Má roinntear é faoi \frac{1}{2}t^{2} cuirtear an iolrúchán faoi \frac{1}{2}t^{2} ar ceal.

$$g=\frac{2\left(s-tv_{0}\right)}{t^{2}}$$

Réitigh do s.

$$s=\frac{t\left(gt+2v_{0}\right)}{2}$$