Réitigh p=a(1-sinθ)

$$p = a ( 1 - \sin \theta )$$

Réitigh do a.

$$\left\{\begin{matrix}a=-\frac{p}{\sin(\theta )-1}\text{, }&\nexists n_{1}\in \mathrm{Z}\text{ : }\theta =2\pi n_{1}+\frac{\pi }{2}\\a\in \mathrm{R}\text{, }&p=0\text{ and }\exists n_{1}\in \mathrm{Z}\text{ : }\theta =2\pi n_{1}+\frac{\pi }{2}\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Athraigh na taobhanna ionas go mbeidh na téarmaí inathraitheacha ar fad ar an taobh clé.

$$a\left(1-\sin(\theta )\right)=p$$

Úsáid an t-airí dáileach chun a a mhéadú faoi 1-\sin(\theta ).

$$a-a\sin(\theta )=p$$

Comhcheangail na téarmaí ar fad ina bhfuil a.

$$\left(1-\sin(\theta )\right)a=p$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(-\sin(\theta )+1\right)a=p$$

Roinn an dá thaobh faoi 1-\sin(\theta ).

$$\frac{\left(-\sin(\theta )+1\right)a}{-\sin(\theta )+1}=\frac{p}{-\sin(\theta )+1}$$

Má roinntear é faoi 1-\sin(\theta ) cuirtear an iolrúchán faoi 1-\sin(\theta ) ar ceal.

$$a=\frac{p}{-\sin(\theta )+1}$$

Réitigh do p.

$$p=a\left(-\sin(\theta )+1\right)$$