Réitigh gt-delta/4(5t-1)=5t+5/8

$$g t - \frac { \delta } { 4 } ( 5 t - 1 ) = 5 t + \frac { 5 } { 8 }$$

Réitigh do g.

$$\left\{\begin{matrix}g=\frac{5\delta }{4}-\frac{\delta }{4t}+5+\frac{5}{8t}\text{, }&t\neq 0\\g\in \mathrm{R}\text{, }&\delta =\frac{5}{2}\text{ and }t=0\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Iolraigh an dá thaobh den chothromóid faoi 8, an comhiolraí is lú de 4,8.

$$8gt-2\delta \left(5t-1\right)=40t+5$$

Cuir 2\delta \left(5t-1\right) leis an dá thaobh.

$$8gt=40t+5+2\delta \left(5t-1\right)$$

Úsáid an t-airí dáileach chun 2\delta a mhéadú faoi 5t-1.

$$8gt=40t+5+10\delta t-2\delta$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$8tg=10t\delta +40t-2\delta +5$$

Roinn an dá thaobh faoi 8t.

$$\frac{8tg}{8t}=\frac{10t\delta +40t-2\delta +5}{8t}$$

Má roinntear é faoi 8t cuirtear an iolrúchán faoi 8t ar ceal.

$$g=\frac{10t\delta +40t-2\delta +5}{8t}$$

Roinn 40t+5+10\delta t-2\delta faoi 8t.

$$g=\frac{5\delta }{4}+\frac{-\frac{\delta }{4}+\frac{5}{8}}{t}+5$$

Réitigh do t.

$$\left\{\begin{matrix}t=-\frac{2\delta -5}{2\left(4g-5\delta -20\right)}\text{, }&g\neq \frac{5\delta }{4}+5\\t\in \mathrm{R}\text{, }&\delta =\frac{5}{2}\text{ and }g=\frac{65}{8}\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Iolraigh an dá thaobh den chothromóid faoi 8, an comhiolraí is lú de 4,8.

$$8gt-2\delta \left(5t-1\right)=40t+5$$

Bain 40t ón dá thaobh.

$$8gt-2\delta \left(5t-1\right)-40t=5$$

Úsáid an t-airí dáileach chun -2\delta a mhéadú faoi 5t-1.

$$8gt-10\delta t+2\delta -40t=5$$

Bain 2\delta ón dá thaobh.

$$8gt-10\delta t-40t=5-2\delta$$

Comhcheangail na téarmaí ar fad ina bhfuil t.

$$\left(8g-10\delta -40\right)t=5-2\delta$$

Roinn an dá thaobh faoi 8g-10\delta -40.

$$\frac{\left(8g-10\delta -40\right)t}{8g-10\delta -40}=\frac{5-2\delta }{8g-10\delta -40}$$

Má roinntear é faoi 8g-10\delta -40 cuirtear an iolrúchán faoi 8g-10\delta -40 ar ceal.

$$t=\frac{5-2\delta }{8g-10\delta -40}$$

Roinn 5-2\delta faoi 8g-10\delta -40.

$$t=\frac{5-2\delta }{2\left(4g-5\delta -20\right)}$$