Réitigh f(x)=x^3-6x^2+11x-6g(x)=x+2

$$f ( x ) = x ^ { 3 } - 6 x ^ { 2 } + 11 x - 6 g ( x ) = x + 2$$

Réitigh do g.

$$g=\frac{x^{2}}{6}-x+\frac{5}{3}-\frac{1}{3x}$$

$$x\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain x^{3} ón dá thaobh.

$$-6x^{2}+11x-6gx=x+2-x^{3}$$

Cuir 6x^{2} leis an dá thaobh.

$$11x-6gx=x+2-x^{3}+6x^{2}$$

Bain 11x ón dá thaobh.

$$-6gx=x+2-x^{3}+6x^{2}-11x$$

Comhcheangail x agus -11x chun -10x a fháil.

$$-6gx=-10x+2-x^{3}+6x^{2}$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(-6x\right)g=2-10x+6x^{2}-x^{3}$$

Roinn an dá thaobh faoi -6x.

$$\frac{\left(-6x\right)g}{-6x}=\frac{2-10x+6x^{2}-x^{3}}{-6x}$$

Má roinntear é faoi -6x cuirtear an iolrúchán faoi -6x ar ceal.

$$g=\frac{2-10x+6x^{2}-x^{3}}{-6x}$$

Roinn -10x+2-x^{3}+6x^{2} faoi -6x.

$$g=\frac{x^{2}}{6}-x+\frac{5}{3}-\frac{1}{3x}$$