Réitigh ax+by=a-b

$$a x + b y = a - b$$

Réitigh do a. (complex solution)

$$\left\{\begin{matrix}a=-\frac{b\left(y+1\right)}{x-1}\text{, }&x\neq 1\\a\in \mathrm{C}\text{, }&\left(b=0\text{ or }y=-1\right)\text{ and }x=1\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain a ón dá thaobh.

$$ax+by-a=-b$$

Bain by ón dá thaobh.

$$ax-a=-b-by$$

Comhcheangail na téarmaí ar fad ina bhfuil a.

$$\left(x-1\right)a=-b-by$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(x-1\right)a=-by-b$$

Roinn an dá thaobh faoi x-1.

$$\frac{\left(x-1\right)a}{x-1}=-\frac{b\left(y+1\right)}{x-1}$$

Má roinntear é faoi x-1 cuirtear an iolrúchán faoi x-1 ar ceal.

$$a=-\frac{b\left(y+1\right)}{x-1}$$

Réitigh do b. (complex solution)

$$\left\{\begin{matrix}b=-\frac{a\left(x-1\right)}{y+1}\text{, }&y\neq -1\\b\in \mathrm{C}\text{, }&\left(a=0\text{ or }x=1\right)\text{ and }y=-1\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Cuir b leis an dá thaobh.

$$ax+by+b=a$$

Bain ax ón dá thaobh.

$$by+b=a-ax$$

Comhcheangail na téarmaí ar fad ina bhfuil b.

$$\left(y+1\right)b=a-ax$$

Roinn an dá thaobh faoi y+1.

$$\frac{\left(y+1\right)b}{y+1}=\frac{a-ax}{y+1}$$

Má roinntear é faoi y+1 cuirtear an iolrúchán faoi y+1 ar ceal.

$$b=\frac{a-ax}{y+1}$$

Roinn a-ax faoi y+1.

$$b=\frac{a\left(1-x\right)}{y+1}$$

Réitigh do a.

$$\left\{\begin{matrix}a=-\frac{b\left(y+1\right)}{x-1}\text{, }&x\neq 1\\a\in \mathrm{R}\text{, }&\left(b=0\text{ or }y=-1\right)\text{ and }x=1\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain a ón dá thaobh.

$$ax+by-a=-b$$

Bain by ón dá thaobh.

$$ax-a=-b-by$$

Comhcheangail na téarmaí ar fad ina bhfuil a.

$$\left(x-1\right)a=-b-by$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$\left(x-1\right)a=-by-b$$

Roinn an dá thaobh faoi x-1.

$$\frac{\left(x-1\right)a}{x-1}=-\frac{b\left(y+1\right)}{x-1}$$

Má roinntear é faoi x-1 cuirtear an iolrúchán faoi x-1 ar ceal.

$$a=-\frac{b\left(y+1\right)}{x-1}$$

Réitigh do b.

$$\left\{\begin{matrix}b=-\frac{a\left(x-1\right)}{y+1}\text{, }&y\neq -1\\b\in \mathrm{R}\text{, }&\left(a=0\text{ or }x=1\right)\text{ and }y=-1\end{matrix}\right.$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Cuir b leis an dá thaobh.

$$ax+by+b=a$$

Bain ax ón dá thaobh.

$$by+b=a-ax$$

Comhcheangail na téarmaí ar fad ina bhfuil b.

$$\left(y+1\right)b=a-ax$$

Roinn an dá thaobh faoi y+1.

$$\frac{\left(y+1\right)b}{y+1}=\frac{a-ax}{y+1}$$

Má roinntear é faoi y+1 cuirtear an iolrúchán faoi y+1 ar ceal.

$$b=\frac{a-ax}{y+1}$$

Roinn a-ax faoi y+1.

$$b=\frac{a\left(1-x\right)}{y+1}$$