Réitigh an^2+16n-26=0

$$a n ^ { 2 } + 16 n - 26 = 0$$

Réitigh do a.

$$a=-\frac{2\left(8n-13\right)}{n^{2}}$$

$$n\neq 0$$

Céimeanna chun Cothromóidí Líneacha a Réiteach

Bain 16n ón dá thaobh. Is ionann rud ar bith a dhealaítear ó nialas agus a shéanadh.

$$an^{2}-26=-16n$$

Cuir 26 leis an dá thaobh.

$$an^{2}=-16n+26$$

Tá an chothromóid i bhfoirm chaighdeánach.

$$n^{2}a=26-16n$$

Roinn an dá thaobh faoi n^{2}.

$$\frac{n^{2}a}{n^{2}}=\frac{26-16n}{n^{2}}$$

Má roinntear é faoi n^{2} cuirtear an iolrúchán faoi n^{2} ar ceal.

$$a=\frac{26-16n}{n^{2}}$$

Roinn -16n+26 faoi n^{2}.

$$a=\frac{2\left(13-8n\right)}{n^{2}}$$

Réitigh do n. (complex solution)

$$\left\{\begin{matrix}n=\frac{\sqrt{2\left(13a+32\right)}-8}{a}\text{; }n=-\frac{\sqrt{2\left(13a+32\right)}+8}{a}\text{, }&a\neq 0\\n=\frac{13}{8}\text{, }&a=0\end{matrix}\right.$$

Réitigh do n.

$$\left\{\begin{matrix}n=\frac{\sqrt{2\left(13a+32\right)}-8}{a}\text{; }n=-\frac{\sqrt{2\left(13a+32\right)}+8}{a}\text{, }&a\neq 0\text{ and }a\geq -\frac{32}{13}\\n=\frac{13}{8}\text{, }&a=0\end{matrix}\right.$$